SOLUTION: How would I graph m=-1/3;b=3 ?

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Question 253112: How would I graph m=-1/3;b=3 ?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Since m=-1/3;b=3, you have the equation y=%28-1%2F3%29x%2B3


Looking at y=-%281%2F3%29x%2B3 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-1%2F3 and the y-intercept is b=3


Since b=3 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is -1%2F3, this means:

rise%2Frun=-1%2F3


which shows us that the rise is -1 and the run is 3. This means that to go from point to point, we can go down 1 and over 3



So starting at , go down 1 unit


and to the right 3 units to get to the next point



Now draw a line through these points to graph y=-%281%2F3%29x%2B3

So this is the graph of y=-%281%2F3%29x%2B3 through the points and


Check out this solver for more help on graphing.