SOLUTION: Can someone help please In 1990, the life expectancy of males was 64.7 years, in 1995 it was 67.8 years. Let E represent the life expectancy inyear t and let t represent the numbe

Algebra ->  Linear-equations -> SOLUTION: Can someone help please In 1990, the life expectancy of males was 64.7 years, in 1995 it was 67.8 years. Let E represent the life expectancy inyear t and let t represent the numbe      Log On


   

Question 250342: Can someone help please
In 1990, the life expectancy of males was 64.7 years, in 1995 it was 67.8 years. Let E represent the life expectancy inyear t and let t represent the number of years since 1990.
E(t)=?t+? round to the nearest tenth
Use the function to predict the life expectancy in 2005
E(15)=? round to the nearest tenth
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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In 1990, the life expectancy of males was 64.7 years, in 1995 it was 67.8 years. Let E represent the life expectancy in year t and let t represent the number of years since 1990.
E(t)=?t+? round to the nearest tenth
:
Find the slope
In 1990; x1=0 and y1=64.7
In 1995; x2=5 and y2=67.8
:
Find the slope (m) using the slope equation: m = %28y2-y1%29%2F%28x2-x1%29
m = %2867.8-64.7%29%2F%285+-+0%29%29 = %283.1%29%2F%285%29 = .62
therefore:
The Linear function E(t) that fits the data is.
E(t)= .62t + 64.7
:
Use the Function to predict the life expectancy in 2005.
This means t=15; substitute 15 for t in the equation
E(15)= .62(15) + 64.7
E(15)= 9.3 + 64.7
E(15)= 74 yrs is the life expectancy in 2005