SOLUTION: I need help putting these into slope intercept form please 1) (-6,8); m=-1/2 2) (-2,7); m=-5 3) (9,-4); m=4/3 4) (0,-3); m=-2/7 5) (12,15);m=1/3 6) (-10,-4);m=-3/5 7) (1,-2)

Algebra ->  Linear-equations -> SOLUTION: I need help putting these into slope intercept form please 1) (-6,8); m=-1/2 2) (-2,7); m=-5 3) (9,-4); m=4/3 4) (0,-3); m=-2/7 5) (12,15);m=1/3 6) (-10,-4);m=-3/5 7) (1,-2)      Log On


   



Question 244835: I need help putting these into slope intercept form please
1) (-6,8); m=-1/2
2) (-2,7); m=-5
3) (9,-4); m=4/3
4) (0,-3); m=-2/7
5) (12,15);m=1/3
6) (-10,-4);m=-3/5
7) (1,-2); m=7

Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
These can all be solved the same way so we'll just do the first one :)
The slope-intercept form of the line equation is Y = (M*X) + B where M is the slope and B is the Y intercept (the value of Y where the line crosses the Y axis (which is also when X = 0).
In this case M is given as -1/2 so, substituting for M, the equation looks like Y = (-1/2)*X + B
Since the line passes through the point (-6,8) we know that when X = -6, Y = 8. Substituting these values for X and Y in the equation above we have:
8 = (-1/2)*(-6) + B
8 = 3 + B
5 = B
So, substituting 5 for B in our slope-intercept form equation above, we then have Y = (-1/2)*X + 5