SOLUTION: find the equation of the line perpendicular to the line 3x-7y+2=0 and passing through the point (3,7)

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Question 243262: find the equation of the line perpendicular to the line 3x-7y+2=0 and passing through the point (3,7)
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
A line perpendicular to 3x-7y+2=0 and passing through the point (3,7)
-7y=-3x-2
y=-3x/-7-2/-7
y=3x/7+2/7 this line has a slope=3/7.
A perpendicular line will have a slope=-7/3
Y=mX+b
7=-7/3*3+b
7=-21/3+b
7=-7+b
b=7+7
b=14 the Y intercept.
Y=-7x/3+14
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+15%2C+-7x%2F3+%2B14%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 15, -7x/3 +14).