SOLUTION: I need a anwser ive tried cant seem to get it right: Write an eqation to a line parellel to 2x-3y=48and goes through (12,-1)

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Question 234611: I need a anwser ive tried cant seem to get it right: Write an eqation to a line parellel to 2x-3y=48and goes through (12,-1)
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Start with:
y+=+mx%2Bb
Since parallel lines have equal slopes, the given equation will have the same slope as the new equation that you are to write, so you need to find the slope of the given equation.
2x-3y+=+48 Add 3y to both sides.
2x+=+3y%2B48 Subtract 48 from both sides.
2x-48+=+3y Divide both sides by 3.
y+=+%282%2F3%29x-16 Compare this with...
y+=+mx%2Bb and you'll see that the slopem+=+2%2F3, so you can start the new equation with:
y+=+%282%2F3%29x%2Bb Now to find b, the y-intercept, simply plug in the x- and y-coordinates of the given point (12,-1) and solve for b.
-1+=+%282%2F3%2912%2Bb Simplify.
-1+=+8%2Bb Subtract 8 from both sides.
b+=+-9 Now you can finish the new equation.
highlight%28y+=+%282%2F3%29x-9%29