SOLUTION: Write the slope intercept form of the equation of the line described. through:(4,2), parallel to {{{-3x/4-5}}}

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Question 224253: Write the slope intercept form of the equation of the line described.
through:(4,2), parallel to -3x%2F4-5

Found 2 solutions by drj, MathTherapy:
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Write the slope intercept form of the equation of the line described.

through:(4,2), parallel to y=-3x%2F4-5

Step 1. We can find the slope by recognizing that parallel lines have the same slope. Since y=-3x%2F4-5 is in slope-intercept form given as y=mx+b where the slope m=-3/4 and the y-intercept b=-5 when x=0 or at point (0,b) or (0,-5).

Step 2. Now we have to find the line with slope m=-3/4 going through point (4,2).

Step 3. The slope m is given as

m=%28y2-y1%29%2F%28x2-x1%29

Step 4. Let (x1,y1)=(4,2) or x1=4 and y1=2. Let other point be (x2,y2)=(x,y) or x2=x and y2=y.

Step 5. Now we're given m=-3%2F4. Substituting above values and variables in the slope equation m yields the following steps:

m=%28y2-y1%29%2F%28x2-x1%29

-3%2F4=%28y-2%29%2F%28x-4%29

Step 6. Multiply x-4 to both sides to get rid of denominator on right side of equation.

-3%28x-4%29%2F4=y-2

-3x%2F4%2B3%2A4%2F4=y-2

-3x%2F4%2B3=y-2

Step 7. Now add 2 to both sides of equation to solve for y.

-3x%2F4%2B3%2B2=y-2%2B2

-3x%2F4%2B5=y


Note: the above equation can be rewritten as

3x%2B4y=20

And the graph is shown below which is consistent with the above steps.

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation 3+x+%2B+4+y+=+20 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-3%2F4.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 20/3 = 6.66666666666667.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 20/4 = 5.
  • Slope is -3/4 = -0.75.
  • Equation in slope-intercept form: y=-0.75*x+5.




I hope the above steps and explanation were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
http://www.FreedomUniversity.TV

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Write the slope intercept form of the equation of the line described.
through:(4,2), parallel to y+=+-3x%2F4+-+5

Parallel linear equations have the same slope, and since the equation of line, y+=+%28-3%2F4%29x+-+5 has a slope, or m of %28-+3%2F4%29, then the slope for the new equation will also have a slope, or m of %28-3%2F4%29.

Using the point-slope formula, y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29, and with y%5B1%5D+=+2_m+=+%28-3%2F4%29_and_x%5B1%5D+=+4, we just need to substitute these values into the point-slope formula to find the equation of the described line.

y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29

y+-+2+=+%28-3%2F4%29%2A%28x+-+4%29

y+-+2+=+%28-3%2F4%29x+%2B+3

highlight_green%28y+=+%28-3%2F4%29x+%2B+5%29