SOLUTION: how can i graph a line that satisfies the conditions of passing through (2,-1) parallel to graph of 2x+3y=6

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Question 222132: how can i graph a line that satisfies the conditions of passing through (2,-1) parallel to graph of 2x+3y=6

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
passing through (2,-1) parallel to graph of 2x+3y=6
3Y=-2X+6
Y=-2X/3+6/3
Y=-2X/3+2 THIS LINE HAS A SLOPE = -2/3. THEREFORE A PARALLEL LINE WILL ALSO HAVE A SLOPE=-2/3
-1=-2/3*2+b
-1=-4/3+b
b=-1+4/3
b=-3/3+4/3
b=1/3 the y intercept.
y=-2x/3+1/3
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-2x%2F3+%2B1%2F3%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10,-2x/3 +1/3).