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Question 214272: write an equation in slope-intercept form of a line satisfying the following conditions: passing through (5,6) and perpendicular to x=7
Answer by drj(1380)   (Show Source):
You can put this solution on YOUR website! Write an equation in slope-intercept form of a line satisfying the following conditions: passing through (5,6) and perpendicular to x=7
Step 1. The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept. The y-intercept occurs at x=0 or point (0,b).
Step 2. x=7 is a vertical line or parallel to the y-axis. So a line perpendicular to x=7 is a horizontal line parallel to the x-axis.
Step 3. Therefore y=b is a horizontal line parallel to the x-axis. Now, the line needs to pass through point (5,6) or x=5 and y=6. Then, y=b=6 or y=6 is the equation of the line.
Step 4. ANSWER: The equation is y=6 where slope m=0 and y-intercept b=6.
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J
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