SOLUTION: what's the equation for points (0,-5) (-3,-2)?

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Question 212018This question is from textbook Precalculus
: what's the equation for points (0,-5) (-3,-2)? This question is from textbook Precalculus

Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
what's the equation for points (0,-5) (-3,-2)?
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Points don't have equations, lines and planes have equation.
Since there are only 2 points, the only type of line that can be defined by them is a straight line, which has a linear equation.
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To find the equation of the straight line passing thru these 2 points, first find the slope, m, of the line.
n = diffy/diffx = (-2-5)/(-3-0)
m = 7/3
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Then use either point in
y-y1 = m*(x-x1)
y+5 = (7/3)x
y = (7/3)x - 5 (slope-intercept form)
7x - 3y = 15 (standard form)

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
what's the equation for points (0,-5) (-3,-2)?

Slope, or m = %28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 = %28-2--5%29%2F%28-3--0%29 = 3%2F%28-3%29 = - 1

Using the point-slope formula, we have:
y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29 -----> y+-+-+5+=+-1%28x+-+0%29
y+%2B+5+=+-x ------> highlight_green%28y+=+-x+-+5%29 --- Slope-intercept form, or,
highlight_green%28x+%2B+y+=+-+5%29 ---- Standard form