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Question 211912: How do you figure out this problem: -5x(2x-1)=3(x+4)
Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! How do you figure out this problem: -5x(2x-1)=3(x+4)
Step 1. Multiply everything out on both sides of the equation. After we mess around with the equation, we will get a quadratic equation. Here it goes:
-5x(2x-1)=3(x+4) will yield: -10x^2+5x=3x+12.
Step 2. Now let's put everything on the right side so that the left side is zero. I like a positive number for the x^2 term.
Step 2a. Add 10x^2 to both sides of equation in Step 1:
10x^2-10x^2+5x=10x^2+3x+12
Note: The 10x^2 terms cancel out on the left side.
Step 2b. Simplify equation in step 2a.
5x=10x^2+3x+12
Step 3. Subtract 5x both sides of equation in Step 2b to make left side =0.
5x-5x=10x^2+3x-12-5x
Note: Collect like terms and simplify 3x-5x=-2x
Step 3a. Simplify to yield our final equation
0=10x^2-2x-12 OR 10x^2-2x-12=0
Step 4. Now we have a quadratic equation in step 3a.
where a=10, b=-2, and c=-12.
Step 5. Substitute a, b, and c in the formula. The steps are shown below:
Note when the quadratic equation is a parabola when the values of x are real numbers. See graph where it intersects the x-axis. This is when y=0, hence our quadratic equation.
Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=484 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: 1.2, -1.
Here's your graph:
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