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Question 211765This question is from textbook COLLEGE ALGEBRA
: variation pls. help
1.) The variable of z varies directly as x and inversely as y.
11.) If z varies jointly as x² and y, and
z = 24 when x = 2 and y = 3, Find the value of z when x = 3 and y = 5.
This question is from textbook COLLEGE ALGEBRA
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! PROBLEM NUMBER 1
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The variable of z varies directly as x and inversely as y.
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z = k*x/y
k is the constant of proportionality.
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PROBLEM NUMBER 2
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If z varies jointly as x^2 and y, and
z = 24 when x = 2 and y = 3, Find the value of z when x = 3 and y = 5.
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z = k*(x^2)*y
k is the constant of proportionality.
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z = 24 when x = 2 and y = 3
This means that:
24 = k*(2^2)*3 = k*4*3 = k*12
divide both sides of equation by 12 to get:
k = 2
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confirming this to be true, we take:
24 = 2*(2^2)*3 = 2*4*3 = 2*12 = 24 confirming the value of k to be 2.
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k = the constant of proportionality = 2
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When x = 3 and y = 5, the value of z would be:
z = 2*(3^2)*5 = 2*9*5 = 18*5 = 90
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Try this website for more info regarding variation:
http://www.purplemath.com/modules/variatn.htm
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