SOLUTION: Please help me understand this. I understand everything except this one. Determine whether the graphs of the given pair of lines are perpendicular. 2x = 3 -3y = 6

Algebra ->  Linear-equations -> SOLUTION: Please help me understand this. I understand everything except this one. Determine whether the graphs of the given pair of lines are perpendicular. 2x = 3 -3y = 6       Log On


   



Question 210645: Please help me understand this. I understand everything except this one.

Determine whether the graphs of the given pair of lines are perpendicular.
2x = 3
-3y = 6

The book says they are perpendicular, but I can't figure out why this is true. Thanks for your help!

Found 3 solutions by Uniquaa, josmiceli, Earlsdon:
Answer by Uniquaa(1) About Me  (Show Source):
You can put this solution on YOUR website!
Wow I just thought about this one, so I guess I can answer my own questions. I sometimes overthink things, because I have math anxiety. just let me know if this is right:

2x=3
x=3/2 (This is a vertical line)

-3y = 6
y=-2 (This is a horizontal line)

They both meet each other at a 90 degree angle, which makes them perpendicular

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1) 2x+=+3
(2) -3y+=+6
Divide both sides of (1) by 2
(1) x+=+3%2F2
Divide both sides of (2) by -3
(2) y+=+-2
The 1st equation has the same value of x
no matter what y is from minus
infinity to plus infinity. It is a
vertical line at x+=+3%2F2
The 2nd equation has the same value of y
no matter what x is from minus
infinity to plus infinity. It is a
horizontal line at y+=+-2
------------------
The lines are therefore perpendicular

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
2x+=+3 Divide both sides by 2.
x+=+3%2F2 This is the equation of a vertical line passing through x+=+3%2F2 Notice that this equation does not include the y-variable and this means that any point that has x+=+3%2F2 and any value of y will lie on the line.
For example, some of the points could include:
(3/2, 7), (3/2, 78), (3/2, 309), etc. The x-value is always the same but the y-value can be any value you choose.
-3y+=+6 Divide both sides by -3.
y+=+-2 This the equation of a horizontal line passing through y+=+-2
This one works just like the previous one only the points could include:
(4, -2), (46, -2), (78, -2), etc. The y-value is always the same but the x-value can be any value you choose.
If you were to plot these points on your coordinate graph paper and join them together, you would see that they make a vertical line in the first case and a horizontal line in the second case.