SOLUTION: solve 1=(y+3)(2y-2)

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Question 210066: solve 1=(y+3)(2y-2)
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for y:
1+=+%28y%2B3%29%282y-2%29 Perform the indicated multiplication on the right side.
1+=+2y%5E2%2B4y-6 Subtract 1 from both sides.
2y%5E2%2B4y-7+=+0 Use the quadratic formula to solve for y:y+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a and here, a = 2, b = 4, and c = -7. Making the appropriate substitutions, we get:
y+=+%28-4%2B-sqrt%28%28-4%29%5E2-4%282%29%28-7%29%29%29%2F2%282%29 Evaluate.
y+=+%28-4%2B-sqrt%2816-%28-56%29%29%29%2F4
y+=+%28-4%2B-sqrt%2872%29%29%2F4
y+=+%28-4%2B6%2Asqrt%282%29%29%2F4 or y+=+%28-4-6%2Asqrt%282%29%29%2F4
y+=+-1%2B%283%2F2%29sqrt%282%29 or y+=+-1-%283%2F2%29sqrt%282%29