SOLUTION: Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB? (with a line above the

Algebra ->  Linear-equations -> SOLUTION: Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB? (with a line above the       Log On


   



Question 205592: Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB? (with a line above the AB - what does that mean?) The answer is (8,1). How was this answer determined?
This is a sample question from a review of questions that I might have on a placement test to determine my math knowledge. I am going back to college for more eduation after many years away from it.
Thank you!

Found 2 solutions by stanbon, Earlsdon:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Point A (-4,1) is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB? (with a line above the AB - what does that mean?) The answer is (8,1). How was this answer determined?
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Draw a coordinate system.
plot the point A(-4,-1)
Draw the verticle line x=2
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Notice that A is 6 to the left of x=2.
Therefore B must be 6 to the right of x=2
B is on the same y-level as A
So B = (2+6,-1) or (8,-1)
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Cheers,
Stan H.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
First, AB with a line above it is shorthand for "line segment AB".
Given point A is (-4, 1).
Now since the line segment AB is bisected by the perpendicular line x = 2, (a vertical line) then you can conclude that the midpoint of line segment AB is at the point (2, 1).
Why, because the line segment AB is horizontal and we know this because the line x = 2 (a vertical line) is the perpendicular bisector of line segment AB, and the line x = 2 must pass through the center of the line segment AB and intersect it at the point (2, 1).
So, using the midpoint formula which gives us the x- and y-coordinates of the midpoint (2, 1):
%28%28x%5B1%5D%2Bx%5B2%5D%29%2F2%29,%28%28y%5B1%5D%2By%5B2%5D%29%2F2%29 where: x%5B1%5D+=+-4 and y%5B1%5D+=+1 substituting, we get:
%28%28-4%2Bx%5B2%5D%29%2F2%29+=+2 and...
%28%281%2By%5B2%5D%29%2F2%29+=+1 we can solve for x%5B2%5D and y%5B2%5D which will be the x- and y-coordinates of point B.
%28-4%2Bx%5B2%5D%29%2F2+=+2 Multiply both sides by 2.
-4%2Bx%5B2%5D+=+4 Now add 4 to both sides.
highlight%28x%5B2%5D+=+8%29 and for the y-coordinate of B...
%281%2By%5B2%5D%29%2F2+=+1 Multiply both sides by 2.
1%2By%5B2%5D+=+2 Subtract 1 from both sides.
highlight%28y%5B2%5D+=+1%29
The coordinates of point B are (8, 1)