SOLUTION: If the degree measure of the smallest angle of a triangle is one-half of the degree measure of the second largest angle and one-third of the degree measure of the largest angle,

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Question 204340: If the degree measure of the smallest angle of a triangle is
one-half of the degree measure of the second largest angle
and one-third of the degree measure of the largest angle,
then what is the degree measure of each angle?
I cannot graph this for the life of me...i tried changing the veribage around it still doesn't work for me please assist.

Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If the degree measure of the smallest angle of a triangle is
one-half of the degree measure of the second largest angle
and one-third of the degree measure of the largest angle,
then what is the degree measure of each angle?
-------------------------------------------------
Let the largest angle measure be "x"
-----
2nd largest measure is (1/3)x
-----
Smallest measure is (1/2)((1/3)x) = (1/6)x
-----------------------------------------------
Equation:
x + (1/3)x + (1/6)x = 180
Multiply thru by 6 to get:
6x + 2x + x = 6*180
9x = 6*180
x = 6*20
x = 120 degrees
(1/3)x = 40 degrees
(1/6)x = 20 degrees
=============================
Cheers,
Stan H.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Let the smallest angle be s

Since the smallest is 1%2F2%29 of the second largest angle, then the second largest angle is twice the smallest angle, or 2s

Since the smallest is also 1%2F3%29 of the largest angle, then the largest angle is thrice the smallest angle, or 3s

Altogether, their sum is 180 degrees. Therefore, we have:

s + 2s + 3s = 180

6s = 180

s = 30

So s, or the smallest angle is: highlight_green%2830%29

The second largest angle is: highlight_green%2860%29 (2*30)

The largest angle is: highlight_green%2890%29 (3*30)