SOLUTION: not sure if I am in the right area, but I have a question about limits compute the following limit: lim x^2+x-12/x-3 x->3

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Question 198056: not sure if I am in the right area, but I have a question about limits
compute the following limit:
lim x^2+x-12/x-3
x->3
Found 3 solutions by solver91311, vleith, stanbon:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Factor the numerator, then eliminate the factor of x - 3 common to both numerator and denominator. That leaves you with x + 4 as x approaches 3, in other words, 7.

John

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%5E2%2Bx-12%29%2F%28x-3%29
%28%28x-3%29%28x%2B4%29%29%2F%28x-3%29
x%2B4
Limit of x+4 as x approaches three is x+4 = 7
Also see this --> http://www59.wolframalpha.com/input/?i=what+is+the+limit+of+(x^2%2Bx-12)%2F(x-3)++as+x+approaches+3

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
compute the following limit:
lim x^2+x-12/x-3
x->3
---------------------
Factor to get [(x+4)(x-3)/(x-3)]
= (x+4)
---------------------
Take the limit as x goes to 3
-----
limit = 7
-------------------------------------
You can see this in the graph:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%28x%5E2%2Bx-12%29%2F%28x-3%29%29
=======================================================
Cheers,
Stan H.