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Question 198031: The graph of the function f(x)=mx+b contains the points (a,2) and (-5,b) express a in terms of b, if the graph is parallel to the line 3x-9y=-5
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
This can't be. If you got this problem from a textbook, go ask for your money back.
if  = mx + b) , then the point ) is guaranteed to be on the graph regardless of the value of  , but if the graph contains the point ) , then the slope of the line must be zero because:
} = 0)
But the slope of
is found by solving for  and taking the coefficient on 
in other words, 
Hence, the two lines cannot be parallel because:
and 
Assuming a slope zero horizontal line,  and  can be anything you like.
On the other hand, if the 'b' in the function definition and the 'b' in the given ordered pair are different values, which is an unconscionably dumb way to express this problem by the way, then you could do the problem. So let's change the 'b' in the ordered pair to  so that we can avoid ambiguity. In that case:
} = \frac{1}{3})
and then all you need to do is solve for in terms of
John
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