|
Question 193088: find the equation of the line containing the points(2,1)and (3,-4)
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! I did one similar yesterday. Follow that method. If you have trouble or want me to check your work, email me via the thank you note.
----------------------
write an equation in slope-intercept form of a line containing the points (-8,9)and (-6,-5).
--------------
There are 2 ways to do these.
Method 1:
Find the slope, m.
m = diffy/diffx
m = (-5-9))/(-6-(-8)) = -14/2
m = -7
Then use either point:
y-y1 = m*(x-x1)
y-9 = -7*(x+8)
y-9 = -7x-56
y = -7x-47
--------------
--------------
Method 2:
|+x +y +1|
|-8 +9 +1| = 0
|-6 -5 +1|
----------
x*(9+5) - y*(-8+6) + (40+54) = 0
14x + 2y +94 = 0
y = -7x - 47
|
|
|
| |
