SOLUTION: Solve the system: x - y + 3z = 23/2 3x + 2y + 2z = -6 2x - z = 1/2

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Question 190106: Solve the system:
x - y + 3z = 23/2
3x + 2y + 2z = -6
2x - z = 1/2
Answer by ronak_hahs(1) About Me  (Show Source):
You can put this solution on YOUR website!
+x-y%2B3z=23%2F2+
Thus,by multiplying both sides by 2
+2x-2y%2B6z=23+ ....(1)
and
+3x%2B2y%2B2z=-6+ ....(2)
By Adding 1 and 2 , we have
+5x%2B8z=17+ ....(3)
Now we consider
+2x-z=1%2F2+
Thus,by multiplying both sides by 2
+4x-2z=1+ ....(4)
By Adding 3 and 4 , we have
+21x=21 i.e +x=1+
Therefore putting value of x in 4,
+4%281%29-2z=1+ i.e +z=3%2F2+
Therefore putting value of x and z in 2,
+2%281%29-2y%2B6%283%2F2%29=23+
i.e +2-2y%2B9=23+
i.e +11-2y=23+
i.e +y=-6+
Therefore
x=1 , y=-6 , z=3/2