SOLUTION: Find the slope of a line perpendicular to 2x + 3y =4 slope=___________ could you break it down to where I might be able to understand it? Thank you!

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Question 189828: Find the slope of a line perpendicular to 2x + 3y =4 slope=____________
could you break it down to where I might be able to understand it?
Thank you!
Found 2 solutions by solver91311, jojo14344:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




The first thing you need to do is put this into slope-intercept () form.

Add -2x to both sides:



Then multiply by



Then the slope of the given line is the coefficient on the x variable.

Next you need to use:



to calculate the slope of a perpendicular.

John

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!


Given Line ---> 2x + 3y =4

Remember Slope-Intercept Form, y=mx%2Bb, wheresystem%28m=Slope%2Cb=yIntercept%29

Going back to our Line Eqn and transforming it to our Slope-Intercept Form:

Isolate "y" by moving "x" to the right: (change sign, + or -)

3y=-2x%2B4, divide "3" the left & right terms:
cross%283%29y%2Fcross%283%29=%28-2x%2B4%29%2F3=%28-2%2F3%29x%2B4%2F3
red%28y=%28-2%2F3%29x%2B4%2F3%29

As per our Slope-Intercept Form, we find Slope=m=-2/3

Now, the line perpendicular to 2x+3y=4 has a Slope=m%5B2%5D=-1%2Fm, negative reciprocal.
So, Slope=m%5B2%5D=-1%2F%28-2%2F3%29=%28-1%29%28-3%2F2%29=highlight%283%2F2%29, Answer

Thank you,
Jojo