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Question 185342: I am having some trouble understanding slopes. I know that M stands for slope, and that slope is a number that tells us how steep a line is and if it is decreasing or inceasing. I dont however, know how to solve something like this: find slope of the line that passes through (1,3) & (2,5). Please help me, I am so lost! thanks.
Found 2 solutions by Alan3354, jojo14344:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! I am having some trouble understanding slopes. I know that M stands for slope, and that slope is a number that tells us how steep a line is and if it is decreasing or inceasing. I dont however, know how to solve something like this: find slope of the line that passes through (1,3) & (2,5). Please help me, I am so lost! thanks.
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it's a lower case m.
It is the "steepness" of the line in the graph. Level, or horizontal, is a slope of zero. It's parallel to the x-axis, and "flat."
The slope, m, is the change in y divided by the change in x.
For those 2 points, it's
(5-3)/(2-1)
= 2/1
m = 2
--------
It's positive, so it increases to the right. y increases 2 for each x increase of 1.
You can graph this on the (free) software from www.padowan.dk.com/graph/
Answer by jojo14344(1513)  (Show Source):
You can put this solution on YOUR website!
In the problem you got 2 points given: (1,3) & (2,5)
Via Point-Slope Form Eqn: 
Net, get the Y-Intercept "b" on point (1,3) via Slope-Intercept Form:
 , Y-Intercept
Also on point (2,5), should be the same because it is a line:
 , Y-Intercept
Your Line Eqn--->
For X-Intercept:
 ----> ---->
Now, let's plot the generated points:
 ----->
*See "Green" points--> : "2" steps up or down; "1" step left or right, FROM THE Y-INTERCEPT "b" (0,1)
See Line passing thru (1,3) & (2,5)
.
Thank you,
Jojo
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