SOLUTION: I can't seem to solve both just one of them, where did I go wrong? Please help. Solve by any method. I tried the addition method. 3x + 2y = -3 2x - 5y = 17 I solved for y but

Algebra ->  Linear-equations -> SOLUTION: I can't seem to solve both just one of them, where did I go wrong? Please help. Solve by any method. I tried the addition method. 3x + 2y = -3 2x - 5y = 17 I solved for y but      Log On


   

Question 179028: I can't seem to solve both just one of them, where did I go wrong? Please help.
Solve by any method. I tried the addition method.
3x + 2y = -3
2x - 5y = 17
I solved for y but when I plugged back in to solve for x it did't work. Thanks.
Found 2 solutions by vleith, checkley75:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
multiply the first one by 2 and the second one by 3. then subtract them
3x+%2B+2y+=+-3
mult by 2 gives
6x+%2B+4y+=+-6
2x+-+5y+=+17
mult by 3
6x+-+15y+=+51
Now subtract one from the other
6x+%2B+4y+=+-6
6x+-+15y+=+51
-------------------
19y+=+-57
y+=+-3

Find x using the first equation and y=-3
3x+%2B+2%28-3%29+=+-3
3x+-6+=+-3+
3x+=+3
x=1
Now use both x = 1 and y = -3 in the second to verify
Does 2%281%29+-5%28-3%29+=+17???
2+%2B+15+=+17 so that works

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
3x + 2y = -3 multiply by 2
2x - 5y = 17 multiply by -3
6x+4y=-6
-6x+15y=-51
------------------
19y=-57
y=-57/19
y=-3 ans.
3x+2*-3=-3
3x-6=-3
3x=-3+6
3x=3
x=3/3
x=1 ans.
Proof:
2*1-5*-3=17
2+15=17
17=17