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Question 176295: 1.Determine the slope that passes through each pair of points.
(-2,-8)(1,4)
2. Write an equation in standard form.
(4,-3) m=2
3. Write an equation in standard form.
(-6,-3)m=1/2
Found 3 solutions by EMStelley, Alan3354, jojo14344:
Answer by EMStelley(208)   (Show Source):
You can put this solution on YOUR website! For the first question, you need to know the equation for slope. If you have two points, (a,b) and (c,d), the slope of the line that passes through them is
m=(d-b)/(c-a)
So the slope of the line passing through (-2,-8) and (1,4) would be
m=(4-(-8))/(1-(-2))=(4+8)/(1+2)=12/3=4
Now, I will help you with the second one, and then you will be able to do the third one on your own:
If you have a point (x1,y1) and a slope m, you can write the equation of the line as
y-y1=m(x-x1)
So in this case we have
y-(-3)=2(x-4)
So
y+3=2x-8
and last, subtract 3 to get
y=2x-11
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! 1.Determine the slope that passes through each pair of points.
(-2,-8)(1,4)
Slope, m, = (diff in y)/(diff in x)
m = (4 -(-8))/(1 -(-2))
m = 12/3
m = 4
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2. Write an equation in standard form.
(4,-3) m=2
I assume you mean thru that point.
y-y1 = m*(x-x1) (x1,y1) is the point
y + 3 = 2*(x-4) = 2x-8
y = 2x-11
2x - y = 11
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3. Write an equation in standard form.
(-6,-3)m=1/2
y-y1 = m*(x-x1) (x1,y1) is the point
y+3 = (1/2)*(x+6)
2y+6 = x+6
x-2y = 0
Answer by jojo14344(1513)  (Show Source):
You can put this solution on YOUR website!
1.Determine the slope that passes through each pair of points.
(-2,-8)(1,4)
Via Point-Slope Form: 
where----->
 ,Slope
.
2. Write an equation in standard form.
(4,-3) m=2
Via PSlope-Intercept Form, 
Subst.
 ----> , Y-Intercept
it follows eqn:  ----> , Standard form
See graph:
.
3. Write an equation in standard form.
(-6,-3)m=1/2
Via Slope-intercept form:
 ---->
Therefore, it follows:
 --------> Standard Form
We'll see the graph:
Thank you,
Jojo
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