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Question 174703: Find the equation, in slop-intercept form; of the line that passes though the points (5,2) and (-7,3). write the equation in slop-intercept form.
Could someone help me with this???? Thank-you so much!!
Found 3 solutions by Mathtut, actuary, Alan3354:
Answer by Mathtut(3670)   (Show Source):
You can put this solution on YOUR website! slope m is found by  change in y over change in x
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m=3-2/(-7-5)=-1/12
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now lets use the point slope formula which states that y-k=m(x-h) where m is the slope and (h,k) is any point on the line. I will use (5,2) as the point
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y-2=(-1/12)(x-5)
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y-2=(-1/12)x+5/12........
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Answer by actuary(112) (Show Source):
You can put this solution on YOUR website! The slope of a line is the rise divided by the run. For the two points given,
the rise is 2-3 = -1. The run is 5-(-7) = 5 + 8 = 13. Therefore the slope is
-1/13. The general two-point formula for a straight line is
y-2 = (-1/13)*(x-5).
This formula can be simplified to y = -1/13*x +5/13 + 2 = -1/13*x + 31/13.
Check the slope intercept formula by substituting for x the value 5. Then
y = -1/13*5 + 31/13 = -5/13 +31/13 = 26/13 = 2 (the value that corresponds to x = 5).
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! Find the equation, in slop-intercept form; of the line that passes though the points (5,2) and (-7,3). write the equation in slop-intercept form.
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|x y 1|
|5 2 1| = 0
|-7 3 1|
x*(2-3)-y*(5-(-7))+(15-(-14)) = 0
-x -12y + 29 = 0
12y = -x + 29
y = (-1/12)x + 29/12
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