SOLUTION: WRITE AN EQUATION OF A LINE THAT PASSES THROUGH THE GIVEN POINT AND IS PERPENDICULAR TO THE GIVEN LINE. (1,-1), Y= 3X+2 PLEASE EXPLAIN AS CLEAR AS POSSIBLE AND PLEASE MAKE

Algebra ->  Linear-equations -> SOLUTION: WRITE AN EQUATION OF A LINE THAT PASSES THROUGH THE GIVEN POINT AND IS PERPENDICULAR TO THE GIVEN LINE. (1,-1), Y= 3X+2 PLEASE EXPLAIN AS CLEAR AS POSSIBLE AND PLEASE MAKE       Log On


   

Question 174056: WRITE AN EQUATION OF A LINE THAT PASSES THROUGH THE GIVEN POINT AND IS PERPENDICULAR TO THE GIVEN LINE.
(1,-1), Y= 3X+2

PLEASE EXPLAIN AS CLEAR AS POSSIBLE AND PLEASE MAKE IT SIMPLE FOR UNDERSTANDING
AND ALSO DO NOT RESTATE ANY UNNESESSARY FORMULAS. I AM ONLY AN 8TH GRADER.
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

Given Line 1: y=3x%2B2---->it follows slope-Intercept form y=mx%2Bb,
where m=Slope=highlight%283%29 and b=yIntercept=2.
In Line 1, we designate Slope as m%5B1%5D.
when 2 lines are perpendicular, the Slope of the other line is "negative reciprocal",
which means m%5B2%5D=-1%2Fm%5B1%5D. Therefore, to get the slope of Line 2 that is perpendicular----->m%5B2%5D=-1%2Fhighlight%283%29=-1%2F3
Then, thru point (1,-1) where x=1 & y=-1,also we use m%5B2%5D=-1%2F3. Via our Slope-Intercept form:
-1=%28-1%2F3%29%281%29%2Bb
-1=-1%2F3%2Bb--->b=-1%2B%281%2F3%29=%28-3%2B1%29%2F3=-2%2F3, Y-intercept:
Then the eqn of Line 2 according to our Slope-Intercept Form: highlight%28y=%28-1%2F3%29x-2%2F3%29 or highlight%28%281%2F3%29%28x%29%2By=-2%2F3%29 STandard Form (Answer)
As we sse the graph:
-------> RED, Line 1 : GREEN, Line 2
Thank you,
Jojo