SOLUTION: 825jane hooker invested $ 40,000 in 3 parts. One part in Mutual fund 2% per year.Second part, amount twice the first, govenment bonds 2.5% per year.the rest in savings account that

Algebra ->  Linear-equations -> SOLUTION: 825jane hooker invested $ 40,000 in 3 parts. One part in Mutual fund 2% per year.Second part, amount twice the first, govenment bonds 2.5% per year.the rest in savings account that      Log On


   

Question 169953This question is from textbook
: 825jane hooker invested $ 40,000 in 3 parts. One part in Mutual fund 2% per year.Second part, amount twice the first, govenment bonds 2.5% per year.the rest in savings account that pays 1.25% annual interest. during the first year, total investment is $ 825. how much did she invest at each rate. This question is from textbook

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.02x+.025*2x+.0125(40,000-3x)=825
.02x+.05x+500-.0375x=825
.0325x=825-500
.0325x=325
x=325/.0325
x=10,000 invested @ 2%
10,000*2=20,000 invested @
40,000-10,000-20,000=10,000 invested @ 1.25%
Proof:
.02*10,000+.025*20,000+.0125*10,000=825
200+500+125=825
825=825