SOLUTION: we have to figure out if the problems down below are linear or non- linear equations, and then have to give an explanation. can you help me ? 2x=3y+1 4xy+2y=7 2x(squared)=4y-3

Algebra ->  Linear-equations -> SOLUTION: we have to figure out if the problems down below are linear or non- linear equations, and then have to give an explanation. can you help me ? 2x=3y+1 4xy+2y=7 2x(squared)=4y-3      Log On


   



Question 169629This question is from textbook Algebra 1
: we have to figure out if the problems down below are linear or non- linear equations, and then have to give an explanation. can you help me ?
2x=3y+1
4xy+2y=7
2x(squared)=4y-3
x/5-4y/3=2
This question is from textbook Algebra 1

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
we have to figure out if the problems down below are linear or non- linear equations, and then have to give an explanation. can you help me ?
2x=3y+1
4xy+2y=7
2x(squared)=4y-3
x/5-4y/3=2
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If they're linear, their graphs will be a straight line, possibly the source of the term linear.
Linear eqns are of "order 1", meaning the exponents are 1. The 3rd eqn has an x^2 term, so it's not linear. The other 3 are linear.