SOLUTION: I'm lost here. Can you help. Once I know how to do one problem I can usually do the rest but my book doesn't explain this one and I am taking online classes so no teacher to a

Algebra ->  Linear-equations -> SOLUTION: I'm lost here. Can you help. Once I know how to do one problem I can usually do the rest but my book doesn't explain this one and I am taking online classes so no teacher to a      Log On


   

Question 164642: I'm lost here. Can you help. Once I know how to do one problem I can usually do the rest but my book doesn't explain this one and I am taking online classes so no teacher to ask. Thanks.
Solve for x. Collect xs on the LEFT side. The solution should be presented with x first, the correct inequality symbol, then the number.
2(x + 3) > 20

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
2%28x%2B3%29%3E20
Yes, x on the left, everything else on the right.
Remember, whatever you do to one side of the equation, you must do to the other side.
%282%28x%2B3%29%29%2F2%3E20%2F2.....Divide both sides by 2.
x%2B3%3E10
x%2B3-3%3E10-3.....Subtract 3 from both sides.
x%3E7.....Final answer.
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Check your answer.
Pick an x>7 and x<7 and plug it into your inequality.
Let's pick x=8 and x=0.
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x=8, should be true since 8>7.
2%28x%2B3%29%3E20
2%288%2B3%29%3E20
2%2811%29%3E20
22%3E20
True.
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x=0, should be false since 0<7.
2%28x%2B3%29%3E20
2%283%29%3E20
6%3E20
False.
Both tests check out.
Good answer.
x%3E7