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Question 158031This question is from textbook
: Review Exercises Chapter 1
Find an equation of the line having the given characteristics. Write the equation using the general form or the slope-intercept form, whichever you prefer. Graph each line.
9. Slope = -3; containing the point (2, -1)
y = -3x - 1 this is where I started
This question is from textbook
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! First let's find the equation of the line
If you want to find the equation of line with a given a slope of which goes through the point (2,-1), you can simply use the point-slope formula to find the equation:
---Point-Slope Formula---
where is the slope, and is the given point
So lets use the Point-Slope Formula to find the equation of the line
Plug in , , and (these values are given)
Rewrite as
Distribute
Multiply and to get
Subtract 1 from both sides to isolate y
Combine like terms and to get
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Answer:
So the equation of the line with a slope of which goes through the point (2,-1) is:
which is now in form where the slope is and the y-intercept is
Since this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is , this means:
which shows us that the rise is -3 and the run is 1. This means that to go from point to point, we can go down 3 and over 1
So starting at , go down 3 units
and to the right 1 unit to get to the next point
Now draw a line through these points to graph
So this is the graph of through the points and
Also, notice how the graph has a slope of -3 (since ) and it goes through the point (2,-1).
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