SOLUTION: find the value of m for which the equation has equal roots (m+1)x2+2(m+3)+(m+8)=0

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Question 155328: find the value of m for which the equation has equal roots (m+1)x2+2(m+3)+(m+8)=0
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!

Note: i think you forgot to put an x after (m+3)
ax%5E2%2Bbx%2Bc has equal roots when b%5E2-4ac=0
%28m%2B1%29x%5E2%2B2%28m%2B3%29x%2B%28m%2B8%29=0 has equal roots when
%282%28m%2B3%29%29%5E2-4%28m%2B1%29%28m%2B8%29=0
then
%282m%2B6%29%5E2-4%28m%5E2%2B9m%2B8%29=0
then
4m%5E2%2B24m%2B36-4m%5E2-36m-32=0
then
-12m%2B4=0
then
m=4%2F12=1%2F3
Answer:m=3