SOLUTION: How would I write these in standard form? Has a slope of 3 and has a y-intercept of 4 Passes through the points (2,-6) and (4,-6) Thanks ryan

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Question 154564: How would I write these in standard form?
Has a slope of 3 and has a y-intercept of 4
Passes through the points (2,-6) and (4,-6)
Thanks
ryan

Found 2 solutions by checkley77, jim_thompson5910:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Y=mX+B (red line)
Y=3X+4 THIS LINE HAS A SLOPE=3 & A Y INTERCEPT=4.
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+3x+%2B4%2C+y+=+-6%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions 3x +4 and y = -6).
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slope=(-6+6)/4-2)=0/2 represents a horizontal line through -6 (green line).

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
# 1

Since the equation has a y-intercept of 4, this means that the line goes through the point (0,4)



If you want to find the equation of line with a given a slope of 3 which goes through the point (0,4), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---

y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point


So lets use the Point-Slope Formula to find the equation of the line


y-4=%283%29%28x-0%29 Plug in m=3, x%5B1%5D=0, and y%5B1%5D=4 (these values are given)


y-4=3x%2B%283%29%28-0%29 Distribute 3


y-4=3x%2B0 Multiply 3 and -0 to get 0


y=3x%2B0%2B4 Add 4 to both sides to isolate y


y=3x%2B4 Add 0 and 4 to get 4


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Answer:


So the equation of the line with a slope of 3 which goes through the point (0,4) is:


y=3x%2B4 which is now in y=mx%2Bb form where the slope is m=3 and the y-intercept is b=4


Notice if we graph the equation y=3x%2B4 and plot the point (0,4), we get (note: if you need help with graphing, check out this solver)


Graph of y=3x%2B4 through the point (0,4)
and we can see that the point lies on the line. Since we know the equation has a slope of 3 and goes through the point (0,4), this verifies our answer.





# 2



First let's find the slope of the line through the points and


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%28-6--6%29%2F%284-2%29 Plug in y%5B2%5D=-6, y%5B1%5D=-6, x%5B2%5D=4, and x%5B1%5D=2


m=%280%29%2F%284-2%29 Subtract -6 from -6 to get 0


m=%280%29%2F%282%29 Subtract 2 from 4 to get 2


m=0 Reduce


So the slope of the line that goes through the points and is m=0


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y--6=0%28x-2%29 Plug in m=0, x%5B1%5D=2, and y%5B1%5D=-6


y%2B6=0%28x-2%29 Rewrite y--6 as y%2B6


y%2B6=0x%2B0%28-2%29 Distribute


y%2B6=0x%2B0 Multiply


y=0x%2B0-6 Subtract 6 from both sides.


y=0x-6 Combine like terms.


y=-6 Simplify


So the equation that goes through the points and is y=-6


Notice how the graph of y=-6 goes through the points and . So this visually verifies our answer.
Graph of y=-6 through the points and