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Question 154564: How would I write these in standard form?
Has a slope of 3 and has a y-intercept of 4
Passes through the points (2,-6) and (4,-6)
Thanks
ryan
Found 2 solutions by checkley77, jim_thompson5910: Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! Y=mX+B (red line)
Y=3X+4 THIS LINE HAS A SLOPE=3 & A Y INTERCEPT=4.
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions 3x +4 and y = -6).
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slope=(-6+6)/4-2)=0/2 represents a horizontal line through -6 (green line).
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! # 1
Since the equation has a y-intercept of 4, this means that the line goes through the point (0,4)
If you want to find the equation of line with a given a slope of which goes through the point ( , ), you can simply use the point-slope formula to find the equation:
---Point-Slope Formula---
where is the slope, and is the given point
So lets use the Point-Slope Formula to find the equation of the line
Plug in , , and (these values are given)
Distribute
Multiply and to get
Add 4 to both sides to isolate y
Add and to get
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Answer:
So the equation of the line with a slope of which goes through the point ( , ) is:
which is now in form where the slope is and the y-intercept is
Notice if we graph the equation and plot the point ( , ), we get (note: if you need help with graphing, check out this solver)
Graph of through the point ( , )
and we can see that the point lies on the line. Since we know the equation has a slope of and goes through the point ( , ), this verifies our answer.
# 2
First let's find the slope of the line through the points and
Start with the slope formula.
Plug in , , , and
Subtract from to get
Subtract from to get
Reduce
So the slope of the line that goes through the points and is
Now let's use the point slope formula:
Start with the point slope formula
Plug in , , and
Rewrite as
Distribute
Multiply
Subtract 6 from both sides.
Combine like terms.
Simplify
So the equation that goes through the points and is
Notice how the graph of goes through the points and . So this visually verifies our answer.
Graph of through the points and
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