SOLUTION: Determine the slope of the line that passes through each pair of points. 1.(5,1) and (2,7) 2.(5,3)and(-2,3) 3.(-1/2,-2)and(-3/2,1) 4.(2,-4)and(2,6)

Algebra ->  Linear-equations -> SOLUTION: Determine the slope of the line that passes through each pair of points. 1.(5,1) and (2,7) 2.(5,3)and(-2,3) 3.(-1/2,-2)and(-3/2,1) 4.(2,-4)and(2,6)      Log On


   



Question 152294: Determine the slope of the line that passes through each pair of points.
1.(5,1) and (2,7)
2.(5,3)and(-2,3)
3.(-1/2,-2)and(-3/2,1)
4.(2,-4)and(2,6)

Answer by Electrified_Levi(103) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, Hope I can help
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Determine the slope of the line that passes through each pair of points.
1.(5,1) and (2,7)
2.(5,3)and(-2,3)
3.(-1%2F2,-2)and(-3%2F2,1)
4.(2,-4)and(2,6)
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The First Points in our problem( (5,1) , (5,3) , ( +-1%2F2+,-2), and (2,-4))
will be (x1,y1) ( In (5,1) 5 = x1, 1 = y1 )
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The Second Points in our problem( (2,7) , (-2,3) , ( +-3%2F2+,1), and (2,6))
will be (x2,y2) ( In (2,6) 2 = x2, 6 = y2 )
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The equation to find the slope is +%28y2-y1%29%2F%28x2-x1%29+
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We can now find the slope in each problem, we will do them one at a time
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Find the slope of a line that passes through (5,1) and (2,7)
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(5,1) (x1,y1) and (2,7) (x2,y2)
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Our equation is +%28y2-y1%29%2F%28x2-x1%29+, we can replace the letters with numbers
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+%28y2-y1%29%2F%28x2-x1%29+ = +%287-1%29%2F%282-5%29+
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+%287-1%29%2F%282-5%29+ = +%286%29%2F%28-3%29+
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+%286%29%2F%28-3%29+ = +-2%2F1+, or (-2)
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The slope of a line that passes through (5,1) and (2,7) is = (-2)
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Now we will solve our second slope
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Find the slope of a line that passes through (5,3)and(-2,3)
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(5,3) (x1,y1) and (-2,3) (x2,y2)
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We can switch the two points, and we can still find the slope
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(-2,3)(x1,y1) and (5,3) (x2,y2)
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( the letters don't change, The first point in a pair will always be (x1,y1), the second point will always be (x2,y2))
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(5,3) (x1,y1) and (-2,3) (x2,y2)
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equation = +%28y2-y1%29%2F%28x2-x1%29+, we will replace letters with numbers
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+%28y2-y1%29%2F%28x2-x1%29+ = +%283+-+3%29%2F%28%28-2%29+-+5%29+
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+%283+-+3%29%2F%28%28-2%29+-+5%29+ = +0%2F+-7+, or "0"
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The slope of a line that passes through (5,3)and(-2,3) is = "0"
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We will solve the third slope
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Find the slope of a line that passes through (-1%2F2,-2)and(-3%2F2,1)
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(-1%2F2,-2)(x1,y1) and (-3%2F2,1) (x2,y2)
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equation = +%28y2-y1%29%2F%28x2-x1%29+, we will replace letters with numbers
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+%28y2-y1%29%2F%28x2-x1%29+ = +%281+-+%28-2%29%29%2F%28%28-3%2F2%29-%28-1%2F2%29%29+
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+%281+-+%28-2%29%29%2F%28%28-3%2F2%29-%28-1%2F2%29%29+ = +3+%2F%28-1%29+, or (-3)
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The slope of a line that passes through (-1%2F2,-2)and(-3%2F2,1) is = (-3)
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We will now solve our last slope
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Find the slope of a line that passes through (2,-4)and(2,6)
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(2,-4) (x1,y1) and (2,6) (x2,y2)
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Our equation = +%28y2-y1%29%2F%28x2-x1%29+, we will replace the letters with numbers
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+%28y2-y1%29%2F%28x2-x1%29+ = +%286-%28-4%29%29%2F%282-2%29+
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+%286-%28-4%29%29%2F%282-2%29+ = +10+%2F+0+, or "no slope"( you can't divide a number by "0")
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The slope of a line that passes through (2,-4)and(2,6) is = "no slope"
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The four slopes are
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1.(5,1) and (2,7) (slope = (-2))
2.(5,3)and(-2,3) (slope = "0")
3.(-1%2F2,-2)and(-3%2F2,1) (slope = (-3))
4.(2,-4)and(2,6) (slope = "no slope")
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Hope I helped, Levi