SOLUTION: Find the intercepts and then use them to graph the equation. 4y-12=4x then graph the line if only one intercept exists use another point to draw the line. I tried 4y-12

Algebra ->  Linear-equations -> SOLUTION: Find the intercepts and then use them to graph the equation. 4y-12=4x then graph the line if only one intercept exists use another point to draw the line. I tried 4y-12      Log On


   



Question 151714: Find the intercepts and then use them to graph the equation.
4y-12=4x
then graph the line if only one intercept exists use another point to draw the line.
I tried
4y-12=4x
y=4
4*4=16-12=4x

oh boy I am confused

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Hang tough.
Intercepts mean one of the coordinates is 0
x intercept has the y coordinate 0.
4y-12=4x
Use y=0
4%2A0-12=4x
-12+=+4x
x=-3
So the x intercept is the point (-3,0)
Y intercept has the x coordinate 0
4y+-12+=+4x
4y+-12+=+4%2A0
4y+=+12
y+=+3+
So the y intercept is (0,3)
If you are given only one intercept, then you need to find a second point before you can plot the line. You need two points to plot a line. So pick a value for x that is not 0 and solve for y.
Let's pick x=1
4y+-+12+=+4x
4y+-+12+=+4%2A1
4y+-12+=+4
4y+=+16
y+=+4
So the second point is (1,4)
Plot the line as follows
graph%28400%2C400%2C+-10%2C10%2C+-10%2C10%2C+x+%2B+3%29