SOLUTION: Find the intercepts and then use them to graph the equation.
4y-12=4x
then graph the line if only one intercept exists use another point to draw the line.
I tried
4y-12
Algebra ->
Linear-equations
-> SOLUTION: Find the intercepts and then use them to graph the equation.
4y-12=4x
then graph the line if only one intercept exists use another point to draw the line.
I tried
4y-12
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Question 151714: Find the intercepts and then use them to graph the equation.
4y-12=4x
then graph the line if only one intercept exists use another point to draw the line.
I tried
4y-12=4x
y=4
4*4=16-12=4x
You can put this solution on YOUR website! Hang tough.
Intercepts mean one of the coordinates is 0
x intercept has the y coordinate 0.
Use y=0
So the x intercept is the point (-3,0)
Y intercept has the x coordinate 0
So the y intercept is (0,3)
If you are given only one intercept, then you need to find a second point before you can plot the line. You need two points to plot a line. So pick a value for x that is not 0 and solve for y.
Let's pick x=1
So the second point is (1,4)
Plot the line as follows