SOLUTION: I need to write this problem into slope-intercept form and i don't know how. passing though (3,6) and (2, -6)

Algebra ->  Linear-equations -> SOLUTION: I need to write this problem into slope-intercept form and i don't know how. passing though (3,6) and (2, -6)      Log On


   



Question 149043: I need to write this problem into slope-intercept form and i don't know how.
passing though (3,6) and (2, -6)

Found 2 solutions by mangopeeler07, Earlsdon:
Answer by mangopeeler07(462) About Me  (Show Source):
You can put this solution on YOUR website!
slope-intercept form: y=mx+b

First solve for m, the slope:
difference of y's over difference of x's [(3,6) and (2, -6)]

6--6/3-2

Simplify
12/1
Slope=m=12

y=12x+b

plug in coordinates (either pair)
6=12(3)+b

Simplify
6=36+b

Subtract 36
-30=b

y=mx+b (don't plug in coordinates now, just m and b)
y=12x+-30

y=12x-30

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the general slope-intercept form of a linear equation:
y = mx+b where m is the slope and b is the y-intercept.
Then find the slope of the line that passes through the points (3, 6) and (2, -6), using the formula:
m+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
In this problem, (x%5B1%5D,+y%5B1%5D) = (3, 6) and (x%5B2%5D,y%5B2%5D) = (2, -6)
Making the apprpropriate substitutions, you get:
m+=+%28-6-6%29%2F%282-3%29 Simplifying...
m+=+-12%2F-1
m+=+12
So now you can write:
y+=+12x+%2B+b but now you need to find the value of b and you can do this by substiting the x- and y-coordinates of either one of the two given points.
Let's use the first point (3, 6) and substitute x = 3 and y = 6 into the above equation.
6+=+12%283%29%2Bb Simplify and solve for b.
6+=+36%2Bb Subtract 36 from both sides.
-30+=+b
Now you can write the final equation because you have m = 12 and b = -30
y+=+12x-30
Let's see what the graph of this equation looks like:
graph%28400%2C400%2C-5%2C5%2C-35%2C15%2C12x-30%29