SOLUTION: r+t/2=7 ;t
Twice the sum of 3 consecutive number odd integers is 150. Find the 3 integers.
I know you start off the problem like this.
x+x+2+x+4=150
then I get 3x+6=150
then
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-> SOLUTION: r+t/2=7 ;t
Twice the sum of 3 consecutive number odd integers is 150. Find the 3 integers.
I know you start off the problem like this.
x+x+2+x+4=150
then I get 3x+6=150
then
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Question 148424: r+t/2=7 ;t
Twice the sum of 3 consecutive number odd integers is 150. Find the 3 integers.
I know you start off the problem like this.
x+x+2+x+4=150
then I get 3x+6=150
then 3x=154
... I'm not sure where I went or if I went wrong.
You can put this solution on YOUR website! r+t/2=7 ;t
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If you mean solve for t
2r + t = 14
t = 14-2r
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Twice the sum of 3 consecutive number odd integers is 150. Find the 3 integers.
I know you start off the problem like this.
x+x+2+x+4=150
Close, but it says "Twice", so it's
2*(x+x+2+x+4)=150
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then I get 3x+6=150
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It's twice that, 6x+12=150
then 3x=154 (should be 144, but that's irrelevant)
... I'm not sure where I went or if I went wrong
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6x+12=150
6x = 138
x = 23
So the integers are 23,25,27
They add up to 75, and twice that is 150.
