|
Question 137412: Please help me , I have three questions.
1. Find the slope of the line that passes thourgh the points (2,3) and (5,8)
2. Find the equation of the line that passes through the points (3,-2)
and (4,-2)
Find the equation, in standard form with all interger coefficients of the line perpendicular to x + 3y = 6 and passing through (-3,5)
Thank you so much for your help
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! 1) slope=(8-3)/(5-2)=5/3 answer.
2) slope=(-2+2)/(4-3)=0/1 which is a horizontal line through the point (y=-2).
3) x+3y=6 or 3y=-x+6 or y=-x/3+6/3 or y=-x/3+2 is the line equation (red line).
the perpendicular line has a slope=3
5=3*-3+b
5=-9+b
b=5+9
b=15 is the y intercept for this line.
y=3x+15 is the line equation for the perpendicular line (green line).
 (graph 300x300 pixels, x from -10 to 16, y from -10 to 16, of TWO functions -x/3 +2 and 3x +15).
|
|
|
| |
