SOLUTION: what is equation of the line through the point(7,-5) and the perpendicular to -3x-2y=-31? which is an equation for the line with x- intercept-3 and y-intercept - 2 ?

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Question 132234This question is from textbook beignner&intermidate alegbra
: what is equation of the line through the point(7,-5) and the perpendicular to -3x-2y=-31?
which is an equation for the line with x- intercept-3 and y-intercept - 2 ?
This question is from textbook beignner&intermidate alegbra

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
-3X-2Y=-31 OR -2Y=3X-31 OR Y=3X/-2-31/-2 OR Y=-1.5X +15.5 (RED LINE)
THE PERPENDICULAR LINE WILL HAVE A SLOPE=1/1.5
-5=7*1/1.5+b
-5=7/1.5+b
b=-5-4.666
b=-9.666 ANSWE RFOR THE Y INTERCEPT
Y=X/1.5-9.666 ANSWER FOR THE LINE THROUGH (7,-5) WITH A SLOPE OF 1/1.5 (GREEN LINE)
+graph%28+300%2C+300%2C+-6%2C+25%2C+-10%2C+18%2C+-1.5x+%2B15.5%2C+x%2F1.5+-9.666%29+ (graph 300x300 pixels, x from -6 to 25, y from -10 to 18, of TWO functions -1.5x +15.5 and x/1.5 -9.666).
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A LINE THROUGH (-3,0) (0,-2) HAS A SLOPE:
(-2,0)/(0-3)
-2/-3 OR 2/3
0=2/3*-3+b
0=-6/3+b
b=6/3
b=2 THE Y INTERCEPT.
Y=2X/3-2 IS THE LINE EQUATION.