SOLUTION: I need to find the slope and y-intercept of each equation and then graph. the first equation is y+3=-1/3x although i am using my book from school my teacher gave me special paper t

Algebra ->  Linear-equations -> SOLUTION: I need to find the slope and y-intercept of each equation and then graph. the first equation is y+3=-1/3x although i am using my book from school my teacher gave me special paper t      Log On


   

Question 131414This question is from textbook Algebra 1
: I need to find the slope and y-intercept of each equation and then graph. the first equation is y+3=-1/3x although i am using my book from school my teacher gave me special paper to do because I wasn't in class because of a broken ankle This question is from textbook Algebra 1

Found 3 solutions by josmiceli, Earlsdon, stanbon:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The slope is defined as the change in y divided by
the change in x. Also, when the equation is in the
form y+=+mx+%2B+b, m is the slope. The y-intercept
occurs where x+=+0, so
y+=+m%2A0+%2B+b
y+=+b is the y-intercept
Your equation is y+%2B+3+=+-%281%2F3%29x
Putting it into the right form,
y+=+-%281%2F3%29x+-+3
m+=+-%281%2F3%29 slope
b+=+-3 y-intercept
I'll graph it, too
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-%281%2F3%29x+-+3%29+

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Well, good luck on your broken ankle!
Write, in slope-intercept form (y = mx+b) and graph:
y%2B3+=+%28-1%2F3%29x Subtract 3 from both sides.
y+=+%28-1%2F3%29x-3 There's the equation in slope-intercept form.
The slope, m+=+%28-1%2F3%29 and the y-intercept, b+=+-3
To graph this, you need only two points, one of which can be found by letting x = 0 then solving for y, and then by letting y = 0 then solving for x. Then you plot these two points on your coordinate graph paper, having previously drawn your x-axis and y-axis, then join the two points with a straight line.
y+=+%28-1%2F3%29x-3 Substitute x = 0.
y+=+-3
y+=+%28-1%2F3%29x-3 Substitute y = 0.
0+=+%28-1%2F3%29x-3 Add 3 to both sides.
3+=+%28-1%2F3%29x Multiply both sides by -3.
-9+=+x
The two points are:
(0, -3) and (-9, 0)
The graph will look like:
graph%28400%2C400%2C-10%2C5%2C-5%2C5%2C%28-1%2F3%29x-3%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I need to find the slope and y-intercept of each equation and then graph. the first equation is y+3=-1/3x although i am using my book from school my teacher gave me special paper to do because I wasn't in class because of a broken ankle
------------------------
y = (-1/3)x - 3
---------
slope = -1/3
y-intercept is -3
-----------------------
Graph:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%28-1%2F3%29x-3%29
Cheers,
Stan H.