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Question 131020: I am having problems with the following:
The solutions of line "a" are (3,3) (5,5)
The solutions of line "b" are (3,-3) (5,-5)
a. Form the equations of both the lines.
b. What are the Co-ordinates of the point of the intersection of lines a and b.
Please use the slope formula and the point slope equation to answer "a"
I think the co-ordiantes is "0". I just can't do the "a" portion. Can somebody help?
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! (3,3) & (5,5)
FIRST WE NEED TO FIND THE SLOPE (Y2-Y1)/(X2-X1)
(5-3)/5-3)
2/2=1 FOR THE SLOPE.
NOW REPLACE THE X & Y TERMS IN THE LINE FORMULA [Y=mX+b] WITH ONE SET OF X & Y VALUES.
3=1*3+b
3=3+b
b=3-3
b=0 SO THE LINE EQUATION THROUGH THESE 2 POINTS IS:
Y=X (RED LINE)
(3,-3) & (5,-5)
(-5+3)/(5-3)
-2/2=-1 IS THE SLOPE OF THIS LINE.
-3=-1*3+b
-3=-3+b
b=-3=3
b=0 OF THE LINE EQUATION THROUGH THESE POINTS IS:
Y=-X (GREEN LINE)
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions x and -x).
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