SOLUTION: Give parallel lines y=x-2 (3,3) i dont know what to do on this problem. Im having a test over it and i have no idea how to do it.I just saw the teacher graph something.

Algebra ->  Linear-equations -> SOLUTION: Give parallel lines y=x-2 (3,3) i dont know what to do on this problem. Im having a test over it and i have no idea how to do it.I just saw the teacher graph something.       Log On


   



Question 128318: Give parallel lines y=x-2 (3,3)
i dont know what to do on this problem. Im having a test over it and i have no idea how to do it.I just saw the teacher graph something.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I think I know what the problem is, but it's not too clear from
your statement of it.
y+=+x+-+2 is the equation of a straight line. You should be able to graph it. All you need is 2 points and draw a line through them. The
easiest points to get are (0,y) and (x,0). Make x+=+0 and
find y, then make y+=+0 and find x
y+=+x+-+2
y+=+0+-+2
y+=+-2 so, the line goes through (0,-2)
0+=+x+-+2
x+=+2 so, the line goes through (2,0)
You need to know the slope of the line
If the line is in the form y+=+mx+%2B+b,
then m is the slope. In this equation,
m+=+1 because it's y+=+1%2Ax+-+2
The problem wants to know what the equation is
that goes through (3,3) and is parallel to
y+=+x+-+2. Since m+=+1, it will look
like y+=+1%2Ax+%2B+b. Substitute (3,3) for
x and y to find b.
3+=+1%2A3+%2B+b
3+=+3+%2B+b
b+=+0
So, the line parallel to y+=+x+-+2 through (3,3)
is y+=+x+%2B+0 or just y+=+x