SOLUTION: I have a 2 questions, they are comfusing me, Laura and Brent paddled a canoe 6 miles upstream in four hours. The return trip took 3 hours. Find the rate at which Laura and

Algebra ->  Linear-equations -> SOLUTION: I have a 2 questions, they are comfusing me, Laura and Brent paddled a canoe 6 miles upstream in four hours. The return trip took 3 hours. Find the rate at which Laura and       Log On


   



Question 126664: I have a 2 questions, they are comfusing me, Laura and Brent paddled a canoe 6 miles upstream in four hours. The return trip took 3 hours. Find the rate at which Laura and Brent paddled the canoe in still water......that is one, and the other is, The sum of the digits of a 2-digit # is 11. If the digits are reversed, the new number is 45 more than the original numer. Find the number
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
You know that distance = rate X time or d=rt, or, since we are trying to determine a rate: r=d%2Ft.

For both the upstream and downstream trips we know the distance is 6 miles and the times, 4 hours and 3 hours respectively.

For the upstream trip, the true rate of speed of the boat is the boat's rate of speed in still water MINUS the rate of the current. For the downstream trip, the true rate is the still water rate PLUS the rate of the current.

Upstream equation: r%5Bs%5D-r%5Bc%5D=6%2F4=3%2F2, where r%5Bs%5D is the rate in still water and r%5Bc%5D is the rate of the current.

Downstream equation: r%5Bs%5D%2Br%5Bc%5D=6%2F3=2

r%5Bs%5D-r%5Bc%5D=3%2F2
r%5Bs%5D%2Br%5Bc%5D=2

Now add the equations, term-by-term:
2r%5Bs%5D%2B0r%5Bc%5D=7%2F2

And solve:
2r%5Bs%5D=7%2F2
r%5Bs%5D=7%2F4

So the rate in still water is 7%2F4 mph.

Check:
To go 6 miles in 4 hours, the true rate must have been 3%2F2 mph. To go 6 miles in 3 hours, the true rate must have been 2 mph.

7%2F4-r%5Bc%5D=3%2F2 means that r%5Bc%5D=1%2F4. 7%2F4%2B1%2F4=8%2F4=2, answer checks.

================================================================
Let the 10s digit be x and the 1s digit be y. The sum of the digits is 11, so:
x%2By=11

And the original number is n, where n=10x+%2B+y

If you reverse the digits, the new number which is 45 more than the old number would be given by:

n%2B45=10y+%2B+x, but this can be written: n=10y%2Bx-45.

Now we have two expressions that are equal to n, so we can set these two expressions equal to each other:

10x%2By=10y%2Bx-45
10x-x-10y%2By=-45
9x-9y=-45
x-y=-5

From our first equation: x%2By=11, we can get y=11-x and we can substitute this expression for y into the previous result:
x-%2811-x%29=-5
2x-11=-5
2x=-5%2B11
2x=6
x=3

Now substituting this value for x into the first equation:
3%2By=11
y=8

So the original number is 38.

Check:
3 + 8 = 11.
83 - 38 = 45. Answer checks.