SOLUTION: Find the equation of the line through the egiven pair of points in standard form using only intergers. (5,1) and (-2,7)

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Question 122776This question is from textbook college algebra
: Find the equation of the line through the egiven pair of points in standard form using only intergers.
(5,1) and (-2,7)
This question is from textbook college algebra

Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First lets find the slope through the points (5,1) and (-2,7)

m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula (note: is the first point (5,1) and is the second point (-2,7))

m=%287-1%29%2F%28-2-5%29 Plug in y%5B2%5D=7,y%5B1%5D=1,x%5B2%5D=-2,x%5B1%5D=5 (these are the coordinates of given points)

m=+6%2F-7 Subtract the terms in the numerator 7-1 to get 6. Subtract the terms in the denominator -2-5 to get -7


m=-6%2F7 Reduce

So the slope is
m=-6%2F7

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Now let's use the point-slope formula to find the equation of the line:



------Point-Slope Formula------
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is one of the given points

So lets use the Point-Slope Formula to find the equation of the line

y-1=%28-6%2F7%29%28x-5%29 Plug in m=-6%2F7, x%5B1%5D=5, and y%5B1%5D=1 (these values are given)


y-1=%28-6%2F7%29x%2B%28-6%2F7%29%28-5%29 Distribute -6%2F7

y-1=%28-6%2F7%29x%2B30%2F7 Multiply -6%2F7 and -5 to get 30%2F7

y=%28-6%2F7%29x%2B30%2F7%2B1 Add 1 to both sides to isolate y

y=%28-6%2F7%29x%2B37%2F7 Combine like terms 30%2F7 and 1 to get 37%2F7 (note: if you need help with combining fractions, check out this solver)



7y=-6x%2B37 Multiply both sides by 7 to clear the fractions


6x%2B7y=37 Add 6x to both sides

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
SLOPE=(7-1)/(-2-5)=6/-7=-6/7
7=-6/7*-2+b
b=7+12/7
b=(49+12)/7
b=61/7
Y=-6X/7+61/7 MULTIPLY ALL TERMS BY 7.
7Y=-6X+61