SOLUTION: solve for x {{{1/8}}}(3x + 2) = {{{1/4}}}(2x + {{{1/2}}})+{{{1/2}}}

Algebra ->  Linear-equations -> SOLUTION: solve for x {{{1/8}}}(3x + 2) = {{{1/4}}}(2x + {{{1/2}}})+{{{1/2}}}      Log On


   

Question 12252: solve for x
1%2F8(3x + 2) = 1%2F4(2x + 1%2F2)+1%2F2
Answer by bonster(299) About Me  (Show Source):
You can put this solution on YOUR website!
1%2F8(3x + 2) = 1%2F4(2x + 1%2F2)+1%2F2
3%2F8x + 2%2F8 = 2%2F4x + 1%2F8+1%2F2
3%2F8x + 2%2F8 = 4%2F8x + 1%2F8+4%2F8
3%2F8x + 2%2F8 = 4%2F8x + 5%2F8 <--subtract 3%2F8x from both sides.
3%2F8x + 2%2F8-3%2F8x = 4%2F8x + 5%2F8-3%2F8x
2%2F8 = 4%2F8x + 5%2F8-3%2F8x
2%2F8 = 1%2F8x + 5%2F8 <--subtract 5%2F8 from both sides
2%2F8-5%2F8 = 1%2F8x + 5%2F8-5%2F8
-3%2F8 = 1%2F8x <--multiply both sides by 8
-3%2F8(8) = 1%2F8x(8)
-3=x