SOLUTION: Graph the {{{highlight(cross(equasion))}}} <U>equation</U> y=-3x+2

Algebra ->  Linear-equations -> SOLUTION: Graph the {{{highlight(cross(equasion))}}} <U>equation</U> y=-3x+2       Log On


   



Question 1208357: Graph the highlight%28cross%28equasion%29%29 equation y=-3x+2

Found 4 solutions by ikleyn, timofer, josgarithmetic, math_tutor2020:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

Go to web-site

www.desmos.com/calculator

Find there free of charge plotting tool.

Print your equation there.

Get the plot in the next instance.



Answer by timofer(104) About Me  (Show Source):
You can put this solution on YOUR website!
Given equation is already in the slope intercept form, so two things you know immediately, point (0,2) is on the graph and slope is -3. Plot the point, find any other point or more based on the slope, and draw the line through the points.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Equation y=-3x%2B2; compare to y=mx%2Bb.
system%28m=-3%2Cand%2C+b=2%29
You know a point and you know the slope for the graphable line.

graph%28400%2C400%2C-6%2C6%2C-6%2C6%2C-3x%2B2%29

Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Plug in x = 0 to get y = 2. This shows (0,2) is one point on the graph. It's the y intercept.

Plug in x = 1 to get y = -1. It leads to the point (1,-1)

Plot the two points (0,2) and (1,-1) on the xy grid. Draw a straight line through them.


Another approach would be to use the y = mx+b template.
m = -3 = -3/1 = slope
b = 2 = y intercept

Start at the y intercept's location (0,2).
Then move down 3 and right 1 to arrive at (1,-1).
This "down 3, right 1" pattern is due to the slope.
slope = rise/run = -3/1
rise = -3 = go down 3
run = 1 = go right 1