SOLUTION: Determine the equation of line with the given properties. Sketch the line. The line is passing through point (4,5) and having a slope of 4. Write in point slope form and standard f

Algebra ->  Linear-equations -> SOLUTION: Determine the equation of line with the given properties. Sketch the line. The line is passing through point (4,5) and having a slope of 4. Write in point slope form and standard f      Log On


   

Question 1208288: Determine the equation of line with the given properties. Sketch the line. The line is passing through point (4,5) and having a slope of 4. Write in point slope form and standard form
Found 3 solutions by josgarithmetic, timofer, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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passing through point (4,5) and having a slope of 4. Write in point slope form and standard form...
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Understanding is necessary.

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passing through point (h,k) and having a slope of m. Write in point slope form and standard form
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One could begin finding for the point slope form first.
m=%28y-k%29%2F%28h-x%29
m%28h-x%29=y-k
y-k=m%28h-x%29-------the point-slope form equation, no matter the given values


y-k=mh-mx
y%2Bmx=mh%2Bk
mx%2By=mh%2Bk-------------this is in form of Ax+By=C.



You were given a specific point on the line, and slope. Plot the point, and use the slope to spot other points and draw the line!



graph%28400%2C400%2C-5%2C15%2C-15%2C5%2C4x-11%29

Answer by timofer(104) About Me  (Show Source):
You can put this solution on YOUR website!
You can plug what is given directly into point-slope equation formula.

y-5=4%28x-4%29
your point-slope equation

Simple algebra steps
y-5=4x-16
y=4x-16%2B5
y=4x-11 which shows you that y intercept is at -11. Enough to draw the graph.

You can put this into 4x-y=11, again very simple algebra.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

In his post,  @josgarithmetic made a fatal error,  which leads him to wrong
final equation as the answer.

The error was that he incorrectly wrote the slope equation for point (h,k) and slope m.

He wrote it in the form   m = %28y-k%29%2F%28h-x%29,   while the correct form is   m = %28y-k%29%2F%28x-h%29.

Therefore,  hist post is toxic,  and my advise to a reader is do not touch it
and do not consider it seriously.

For the solution,  use the correct post by @timofer.

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To see many other similar solved problems with detailed explanations,  look into the lesson
    - Equation for a straight line having a given slope and passing through a given point
in this site.

Learn the subject from there once and for all.