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Question 1206960: write the equation of the line that is parallel to the line -3x-9y=4 and passes through (9,2)
Found 3 solutions by mananth, greenestamps, ikleyn:
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! write the equation of the line that is parallel to the line -3x-9y=4 and passes through (9,2)
line -3x-9y=4
9Y=-3x -4
divide by 9
y= (-3/9)x -(4/9)
compare with
y= mx+b
slope m = (-3/9) = -1/3
The slope of the paralel line will be the same = (-1/3)
It passes through (9,2)
plug the cordinates to get the value of b
2= (-1/3)(9)+ b
2=-3 +b
b = 5
we know m and b
so the equation will be
y = (-1/3)x +5
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
Given the equation -3x-9y=4 of the given line, any line parallel to that line has an equation in the form -3x-9y=A for some constant A.
Given that the point (9,2) is on that parallel line, substitute x=9 and y=2 to determine the constant A.
-3(9)-9(2)=-27-18=-45
ANSWER: -3x-9y=-45
Answer by ikleyn(52781)  (Show Source):
You can put this solution on YOUR website! .
write the equation of the line that is parallel
to the line -3x-9y=4 and passes through (9,2)
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A  writing to this problem would be
write  an equation of the line that is parallel
to the line -3x-9y=4 and passes through (9,2)
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