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Question 120677: A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture?
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Let x = amt of $12 coffee required
It said that a total of 100lb is required, therefore
Let (100-x) = amt of $9 coffee required
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12x + 9(100-x) = 11.25(100)
12x + 900x - 9x = 1125
12x - 9x = 1125 - 900
3x = 225
x = 225/3
x = 75 lb of $12 coffee, obviously that leaves 25 lb of $9 coffee required
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Check solution in original equation
12(75) + 9(25) = 1125
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Not that hard, right?
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