SOLUTION: For Open House in the year 2006, there were
60 tours. In the year 2010 there were 66
tours. Assuming this rate remains constant,
predict how many tours will be given in the
yea
Algebra ->
Linear-equations
-> SOLUTION: For Open House in the year 2006, there were
60 tours. In the year 2010 there were 66
tours. Assuming this rate remains constant,
predict how many tours will be given in the
yea
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Question 1203375: For Open House in the year 2006, there were
60 tours. In the year 2010 there were 66
tours. Assuming this rate remains constant,
predict how many tours will be given in the
year 2024. Create an equation to represent
this situation and graph it.
You can put this solution on YOUR website! 60 in 2006
66 in 2010
since this is in linear equations, the rate is assumed to be a certain number per year.
1006 to 1020 is 4 years.
your rate is 6 tours divided by 4 years = 6/4 tours per year.
thaat's a growth of 1.5 tours per year.
in 2006 = 60
in 2007 = 61.5
in 2008 = 63
in 2009 = 64.5
in 1010 = 66
your equation will be y = 1.5x + 60
x = 0 is the same as the year 2006.
the graph would look like this.
the graphing software is at https://www.desmos.com/calculator
in the year 2024, the number of tours will be 1.5 * (2024 - 2006) + 60 which is equal to 1.5 * 18 + 60 = 87
