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Question 1202850: In 2010, the estimated population of Pottsville, USA was 31,713 people. By 2011, the population had grown to 32,928 people.
Assuming that the growth is linear, construct a linear function
that expresses the population of Pottsville
years since 2010 and use it to predict the population in the year 2015.
L(t)=
Round to the nearest thousandth as needed.
If this growth rate continues, the population in the year 2015 will be approximately
people.
Round your answer to the nearest person.
Assuming that the growth is exponential, construct an exponential function
that expresses the population of Pottsville
years since 2010 and use it to predict the population in the year 2015.
Round to the nearest thousandth as needed.
If this growth rate continues, the population in the year 2015 will be approximately
people.
E(t)=
Round your answer to the nearest person.
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! -------------------------
2010, the estimated population of Pottsville, USA was 31,713 people. By 2011, the population had grown to 32,928 people.
Assuming that the growth is linear, construct a linear function
that expresses the population of Pottsville
years since 2010 and use it to predict the population in the year 2015.
L(t)=
-----------------
Two points using 0 for x at year 2010,
(0,31713) and (1,32928);
Use either point,
but easiest to pick the first point;
 --------to make quick use of slope-intercept form.
Now for the question about year 2015,  , and compute.
To use an EXPOENTIAL growth model,
or maybe a little quicker,
the same two points,
 ,
which is simply
model may be stated 
Use this for x at 5 to answer second question.
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