|
Question 1197246: Two factory plants are making TV panels. Yesterday, Plant A produced 6000 fewer panels than Plant B did. Five percent of the panels from Plant A and 4% of the panels from Plant B were defective. How many panels did Plant B produce, if the two plants together produced 690 defective panels?
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
Two factory plants are making TV panels. Yesterday, Plant A produced 6000 fewer panels than Plant B did.
Five percent of the panels from Plant A and 4% of the panels from Plant B were defective.
How many panels did Plant B produce, if the two plants together produced 690 defective panels?
~~~~~~~~~~~~~~~
x = the number of panels Plant B produced yesterday.
Plant A produced (x-6000) panels.
Total defective panels equation
0.05*(x-6000) + 0.04x = 690
Simplify and find x
0.05x - 300 + 0.04x = 690
0.09x = 690 + 300 = 990
x = 990/0.09 = 11000.
ANSWER. Yesterday, plant B produced 11000 panels.
Solved.
|
|
|
| |
